Question

A person is pulling an object with a rope and exerting 5N force such that rope is making an angle 300

from the

horizontal. Calculate the work done in displacing the object to 20m
(cos30.=under root 3/2or 0. 866)

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Answer 1

Explanation:

F horizontal=Force X Angle made

Which is

F horizontal= 5 X cos 30= 5 root 3/2

Now Workdone= Force X Displacement

= 5 root 3/2 X 20= 50 root 3 or 43.3 Nm

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