Question

A person is standing exactly 36 ft from a telephone pole. There is a 30° angle of elevation from the ground to the top of the pole.



What is the height of the pole?

Answer 1

here is your answer buddy

Answer 2

$The \:height \: of\:telephone \:pole = AB \: ft$

$Distance \: between \:the \:person \: to \: foot \: of \:the \:pole ( BC ) = 36 \:ft$

$Angle \:of \: elevation = 30\degree$

$In \triangle ABC, \:we \:have , \\tan 30\degree = \frac{AB}{BC}$

$\implies \frac{1}{\sqrt{3}} = \frac{AB}{36}$

$\implies \frac{36}{\sqrt{3}} = AB$

$\implies \frac{36 \times \sqrt{3}}{\sqrt{3}\times \sqrt{3}} = AB$

$\implies \frac{36 \times \sqrt{3}}{3} = AB$

$\implies AB = 12 \sqrt{3}$

$\implies AB = 12 \times 1.732$

$\implies AB = 20.78 \:ft$

Therefore.,

$\red{Height \:of\:telephone \:pole}\green {= 20.78 \:ft }$

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