Question

a person is throwing balls into the air one after other . he throws the second ball when first ball is at the heighest point . if he is throwing two balls every second ,how high do they rise

Answer 1

A person is throwing balls into the air one after the other. He throws the second ball when first ball is at the highest point. If he is throwing 2 balls every second, how high do they rise?

What is the revenue generation model for DuckDuckGo?

It is given that he throws the next ball after the previous one reaches to top.

It is also given that he is throwing 2 balls each second.

Which means after 0.5 second, the ball reaches its maximum height.

Now,

h=?

u=v+gt (v=u-gt)

u=0+10*0.5

u=5 m/s

v=0 m/s

Putting these in the equation v^2 - u^2=-2gh

0–5^2 = -2×10×h

h=1.25 m.

Answer 2

Answer:

Explanation:

It is also given that he is throwing 2 balls each second.

Which means after 0.5 second, the ball reaches its maximum height.

Now,

h=?

u=v+gt (v=u-gt)

u=0+10*0.5

u=5 m/s

v=0 m/s

Putting these in the equation v^2 - u^2=-2gh

0–5^2 = -2×10×h

h=1.25 m.

Read more on Brainly.in - https://brainly.in/question/6927452#readmore