A person is travelling at 120/hr after 10 seconds its velocity changes to 140 km/ hr. Assuming the velocity changes took place at a uniform rate, find his acceleration
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(673 x 86) + (673 x 24) - (673 x 60) (ii) (42 x 12) + (42 x 27) + (42 x 11) (iii) (74 x 126) - (74 x 32) + (74 x 16) (iv) (424 x 12) – (424 x 6) + (424 x 4) (v) (342 X 63) + (342 x 37) – (342 x 99) (vi) (212 x27)+(23 x 212) (vii) (9165 x 46) - (9165 x 26) (viii) (8192 x 58) - (8 X 8192) (ix) (674 X 71) + (49 x 674) + (30 x 674) (x) (55,321 x 92) + (8 x 55,321) (xi) (583 x 36) + (583 x 17) - (48 x 583) -
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