Question

if (x-2) and (x-3) are factors of x^2-ax+p, then value of p is​

Answer 1

Answer:

$x - 2 = 0 \\ x = 2$

$x - 3 = 0 \\ x = 3$

${x}^{2} - ax + p \\ subtistude \: 2 \: in \: place \: of \: x \: \\ {x}^{2} - 2a + p$

$subtistude \: 3 \: now \\ {x}^{2} - 3a + p$

hope this may help you

Answer 2

Answer:

nice pfp

tonymotana

lachibolala

may I get that pls