A person jogged 10 times along the perimeter of a rectangular field at the rate of 12 kms per hour for 30 minutes. If the field has a length that is twice its width, find the area of the field in square meters.
Answers
Answered by
7
the length moved by man is 20(l+b)
where l-length b-width of the field
its speed is 12km/hr
so the distance/time=12
20(l+b)/(0.5)=12
l+b=6/20 km
as l=2b
3b=6/20
b=1/10 km
l=2/10 km
area of the field=lb=(1/10)(2/10)=1/50 km^2
where l-length b-width of the field
its speed is 12km/hr
so the distance/time=12
20(l+b)/(0.5)=12
l+b=6/20 km
as l=2b
3b=6/20
b=1/10 km
l=2/10 km
area of the field=lb=(1/10)(2/10)=1/50 km^2
Answered by
0
Answer:
go be the first one to the answer
Similar questions
Math,
8 months ago
Science,
8 months ago
Math,
1 year ago
Social Sciences,
1 year ago
Math,
1 year ago