a person jogging towards east moves up to 3 km and then takes a left and runs up to 4 km. how far he is from its starting point ? Also, find the average speed and average velocity if he takes 20 minutes to complete his journey
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3km in east then turns to left I.e north and move 4km. Let us consider the starting point as origin. So displacement of the the person is equal to its distance from starting point and by Pythagoras theorem displacement of person =(3^2+4^2)^1/2 = 5km
Average speed = total distance travelled/total time
•Time in hours equal = 20/60=1/3
Average speed=(3+4)*3= 21km/hr
Average velocity= displacement/total time
=5*3=15km/hr in north-east direction.
Average speed = total distance travelled/total time
•Time in hours equal = 20/60=1/3
Average speed=(3+4)*3= 21km/hr
Average velocity= displacement/total time
=5*3=15km/hr in north-east direction.
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