a person moves 30 m north and then 20 m east and finally 30 root 2 m south west what is the displacement from the original position?
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Answered by
5
See the figure given.
CD = 30√2 m
We need to find AC:
AC = √(30)² + (20)²
AC = 10√13 m
Then,
Displacement = CD - AC
= 6.4m
CD = 30√2 m
We need to find AC:
AC = √(30)² + (20)²
AC = 10√13 m
Then,
Displacement = CD - AC
= 6.4m
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Answered by
0
you can see in the figure ,
He starts from origin and he moves 30 m North , then 20m East then finally 30√2m South- west .
displacement = final position - initial position .
displacement = OC
= BC - BO
here BC = 30√2 m
and BO = √{30² + 20² } = 10√13 m
hance,
displacement = (30√2 - 10√13 )m
= 6.37 m
He starts from origin and he moves 30 m North , then 20m East then finally 30√2m South- west .
displacement = final position - initial position .
displacement = OC
= BC - BO
here BC = 30√2 m
and BO = √{30² + 20² } = 10√13 m
hance,
displacement = (30√2 - 10√13 )m
= 6.37 m
Attachments:
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