Question

a person moves 6 kilometre west and then moves 8 km towards south calculate distance and displacement​

Answer 1

Distance depends on the path. So if the points are o, w, n….then ‘o’ to west ‘w’ that is ‘ow’ = 6 km and like that’w’ to ‘n’ “wn”=8 km

Now the distance will be the total of (‘ow’+‘wn’)= 6+8= 14 km

But displacement does not depend on the path the body passes, instead it depends on initial and ending point..

If we consume a triangle connecting the point o, w, n… then it will be an equiangular triangle… and the initial point of movement of that body is ‘o’ and and the ending point is ‘n’

So the displacement of the body will be ‘o’ to ’n’ that is ‘on’ which is hypotenuse of the equitrianglur triangle.. now to get the value of ‘on’ u have to apply ‘Pithagoras’s law’—

on^2=ow^2+wn^2=6^2+8^2=36+64=100

on^2=100

And, on=10km (displacement)

i hope u can understand

PLSS MAKE THIS BRAINLIEST

Answer 2

Answer:

distance = total path length covered by a particle .

distance = (6+8) km = 14 km

distance = shortest straight line distance between initial and final position of the particle .

as he moves 6km west and 8km south the shortest straight line distance would be the hypotenuse . therefore , displacement = root (6^2+8^2) = 10 km south west

Explanation: