Physics, asked by sauravkumar977125509, 10 months ago

A person moves a to b with a speed of 40 kilometre per hour he returned back b2a with same speed if the average speed of the person in the whole journey system kilometre per hour find the speed with which he returned back from b to a

Answers

Answered by Agamsain
1

Answer:

Let the Distance between A and  is x km.

First Case---

Initial Speed = 40 km/hr.

Using the Formula,

  Speed = Distance/Time

        time = Distance/Speed

        time(t1) = x/40 hr.

In second Case,

Final Speed = 60 km/hr.

Thus, time(t2) = x/60 km/hr.

For Average Speed,

 Total Distance covered by the Car = x + x

                                                        = 2x km.

Total time = t1 + t2

                = x/40 + x/60

                = (4x + 2x)/120

                = 6x/120

                = x/20 hrs.

Using the Formula,

 Average Speed = Total Distance/Total Time

                          = 2x/(x/20)

                          = 2x × (20/x)

                          = 2 × 20

                         = 40 km/hr.

Thus, Average Speed of the Car is 40 km/hr.

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