Question

A person moves along the boundary of a square park of side 10 m in 40 s.what will be the magnitude of displacement of the person at the end of 3 minutes

Answer 1

3min / 40s= 9/2 rotations
so the person has completed 4 revolutions
and also has completed his .5 rotation
we know displacement= delta x
=
$10 \sqrt{2}$
m