Question

A person moving at speed of 5kms-1makes an elastic collision with an other proton initially at rest. Give that after collision the moving proton moves at an angle 37 degree with speed V1 and proton at rest moves at angle of theta 2 in downward direction with x axis with speed V2. Find V1, V2and theta 2

Answer 1

Answer:

axis = 900/ v2 square with speed if 93 km per hr