A person moving on motor cycle in a ground takes turn through 60° on his left after every 50m. Then find the magnitude of displacement suffered by him after 9th turn
Answers
Answer:
0
Explanation:
because it is equilateral triangle he turned 9 times in equilateral triangle and he returns to same place where he has started
The magnitude of the displacement suffered by the person moving a motor cycle after 9th turn is 100 m
Explanation:
On taking the turn of 60° every 50 m, the motorcyclist will complete a full hexagon after 6 turns and return to point A as shown in figure
On 7th , 8th and 9th turn he will go from A to G, then from G to H and then from H to I respectively
Initial starting point = A
Final ending point = I
Thus, the displacement = AI = AD
In ΔBCD
DC = BC = 50 m
∠BCD = 120°
∴ ∠CBD = ∠CDB = 30°
∴ ∠ABD = ∠ABC - ∠CBD = 120° - 30° = 90°
Thus ΔABD is a right angled triangle
In ΔBCD, by sine rule
Therefore, in right angled ΔABD
m
Therefore, the magnitude of displacement is 100 m
Hope this answer is helpful.
Know More:
Q: What is mean by magnitude of displacement ?
Click Here: https://brainly.in/question/9727153
Q: A man walks 4m north then 3m East. the magnitude of displacement of man is:
Click Here: https://brainly.in/question/11933975