a person observed that angle of elevation of the top of a electrical pole as 30 . he walked 5 meters towards the foot of the tower along level ground and found the angle of elevation of the top of the pole as 60. draw a suitable diagram
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In case 1 the angle of elevation is 30
In case 2 the angle of elevation is 60
In case 2 the angle of elevation is 60
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We will assume h be the height of the building.
ΔABC tan 60° = AB/BC
√3 = h/x
x = h/√3
And in the Right Angle ABD,
tan 30° = AB/BD
= 1/√3 = h/ x + 50
= h/√3 + 50 = √3h
h = 25√3m
If there is any confusion please leave a comment below.
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