Question

A person observes a change of 2.5 % of in frequency of sound of horn of a car if the car is approaching forward the person and sound velocity is 320 m per second the velocity of car will be

Answer 1

Hey dear,

◆ Answer-
v' = 7.8 m/s

◆ Explaination-
# Given-
v = 320 m/s
f'/f = 102.5%

# Solution-
Let f be original frequency of source, and f' be apparent frequency. Also v be sound velocity and v' be car velocity.

Apparent frequency is calculated by-
f' = fv / (v-v')
f'/f = v / (v-v')
102.5/100 = 320 / (320-v')
32000 = 32800 - 102.5v'
v' = 800 / 102.5
v' = 7.8 m/s

Therefore, velocity of the car must be 7.8 m/s.

Hope it helps...

Answer 2

plz mark as brainliest answer