A person of mass 70 kg climbs a tower of
height 60 m. What is the work done by him against gravity?
Answers
Answered by
14
Answer:
Work done = m*g*h
W = 70*9.8*60 = 41,160 J
W = 41.16 kJ
Answered by
7
Answer:
41.16 kj is the answer
like my answer
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