A person of mass 70 kg jumps out of a boat of mass 350 kg onto the bank with a
velocity of 3 m/s. With what velocity does the boat begin to move backwards?
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Given A person of mass 70 kg jumps out of a boat of mass 350 kg onto the bank with a velocity of 3 m/s. With what velocity does the boat begin to move backwards?
- Mass of the person m1 = 70 kg
- Mass of the boat m2 = 350 kg
- Velocity v1 = 3 m/s
- Initial momentum of the boat and the person = m1u1 + m2u2 = 0
- Final momentum of the boat and the person = m1v1 + m2v2
- = 70 x 3 + 350 x v2
- By law of conservation of momentum we get
- m 1 u1 + m2u2 = m1v1 + m2v2
- 0 = 70 x 3 + 350 x v2
- 0 = 210 + 350 v2
- So 359 x v2 = - 210
- So v2 = - 210 / 350
- So v2 = - 0.6 m/s
The boat begins to move backwards with a velocity of 0.6 m/s. the negative sign indicates the direction of the velocity of person and direction of the velocity of boat are opposite to each other.
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