Physics, asked by Anonymous, 1 year ago


A person of mass 'm' is standing in a lift. Find his apparent weight when lift is (show mathematical
calculation)
1.moving upward with uniform acceleration 'a'.
2.moveing downward with uniform acceleration 'a' (a<g)
3.falls freely​

Answers

Answered by siddhivinayaktidake
9

Answer:

Hey I know.

Explanation:

1. mg+ma

2. mg-ma

3. When lift falls freely it's apperent weight is zero.

Because of its free fall.

Attachments:
Answered by Abhijeet1589
7

The apparent weight of the person-

1. when the lift is moving upward acceleration- m(g+a)

2. moving downward with uniform acceleration m(g-a)

3. falls freely - zero.

GIVEN

Mass of a person = m

1. lift moving upward with acceleration a

2. lift moving downward with acceleration a.

TO FIND

Apparent Weight of the person.

SOLUTION

(1) LIFT MOVING UPWARD WITH UNIFORM ACCELERATION :

when the lift is in rest position,

The force by the person on the lift is in the downward direction.

The force on the lift by the person = Weight of person

when the lift is at rest,

weight of person = m×g (g=acceleration due to gravity

When Lift Is Moving In Upward Direction-

when lift starts moving in an upward direction, a Reaction force is applied to the person opposite to the direction of acceleration.

In this case, the Direction of Reaction force is in the downward direction.

Reaction force, F = m × a

Apparent weight = Initial weight + Reaction force

= mg + ma

Apparent weight = m(g+a)

Hence, The apparent weight of the person when the lift is moving in the upward direction is m(g+a).

(2) LIFT MOVING DOWNWARD WITH UNIFORM ACCELERATION :

when the lift starts moving in a downward direction, a Reaction force is applied to the person opposite to the direction of acceleration.

In this case, the Direction of reaction force is in an upward direction.

Reaction force, F = m × a

Apparent weight = Initial weight - Reaction force

= mg - ma

Apparent weight = m(g-a)

(3) FALLS FREELY:

When the lift falls freely.

There is no reaction force that the body can exert on the left.

Hence, the apparent weight of a person under free fall is zero.

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