Question

a person of normal eye sight can read point at such a distance that the letters suntend an angle of 5 min at the eye , find the height of the letters he can read at a distance of 420



please answer it on details so that i can understand by once.​

Answer 1

Answer:

Given:

Letters subtend an angle of 5' (read as 5 minutes.)

Distance between eye and letters is 2640 m.

To find:

The height of letters = ?

Solution:

Please refer to the attached figure which depicts the given situation in the form of a right angle triangle .

A is the location of eye.

The letters are at point B and point C subtends the angle of 5' on eye.

We have to find the side BC of the triangle (Height of the letters).

We can use trigonometric identities to solve for side BC.

First of all, let us convert given angle to degrees:

Now, let us use tangent:

$<a = 5 = \frac{5 {}^{o} }{60} = 0.083 {}^{o}$

In the given triangle:

$tan0 = \frac{perticular}{base}$

So, the height of letters is 3.824 m.

Step-by-step explanation:

hope it helps you. please make me brainlest and thank me

Answer 2

Sorry I don’t know :(Isndhdidibsjdurjdvskdhdgsueuehhehrhdhddhdhdhdhhdhdhd