Question

a person on tour has ₹4200 for his expenses. If he extends his tour for 3 days, he has to cut down his daily expenses by ₹70. Find the original duration of the tour

Answer 1

Let the original duration of tour be x days
Amount with the person is Rs 4200
Daily expenses = Rs (4200/x)
Given tour extended for 3 more days
Hence total number of days = (x + 3) days
Daily expenses = Rs [4200/(x + 3)]
By the given problem, we have

(x + 15)(x – 12) = 0
Hence x = 12 as x cannot be negative
Thus the original duration of tour is 12 days.

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Kishore , Student

Member since Dec 10 2008

Let the original duration of tour be x days
Amount with the person is Rs 4200
Daily expenses = Rs (4200/x)
Given tour extended for 3 more days
Hence total number of days = (x + 3) days
Daily expenses = Rs [4200/(x + 3)]
By the given problem, we have

(x + 15)(x – 12) = 0
Hence x = 12 as x cannot be negative
Thus the original duration of tour is 12 days.

Hope this Helps.

Answer 2

The attachment is the solution.
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