Question

Calculate the force required to move a train of 200 quintal up on an incline plane of 1 in 50 with an acceleration of 2 ms2. The force of friction per quintal is 0.5 N?

Answer 1

mass = m= 200 quintal or 20000 kg
sin0= 1/50 
acceleration= a = 2
Force of friction = o.5 N

Force = ma 
= 200 x 0.5 
= 100N

While moving upwards, force required against gravity= mg sin0
= 20000 x 9.8 x 1/50
= 3920 N

Force required to produce this acceleration = 20000 x 2= 40,000 N

total force = 100 + 3920 + 40000
= 44020 N

Answer 2

Explanation:

mass = m= 200 quintal or 20000 kg

sin0= 1/50 

acceleration= a = 2

Force of friction = o.5 N

Force = ma 

= 200 x 0.5 

= 100N

While moving upwards, force required against gravity= mg sin0

= 20000 x 9.8 x 1/50

= 3920 N

Force required to produce this acceleration = 20000 x 2= 40,000 N

total force = 100 + 3920 + 40000

= 44020 N