A person on tour has Rs.360 for his expenses . If he extends his tour for 4 days , he has to cut down his daily expenses by Rs. 30. Find the original duration of the tour.
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Answer:
Amount with the person = Rs 360
Let the original number of duration of the tour be x days
Daily expenses per day = Rs 360/xGiven that his tour is extended for 4 days
Hence per days = Rs 360/(x + 4)
∴
⇒ 360x + 1440 – 360x = 3(x2 + 4x)
⇒ 1440 = 3x2 + 12x
⇒ 3x2 + 12x – 1440 = 0
⇒ x2 + 4x – 480 = 0
⇒ x2 + 24x – 20x – 480 = 0
⇒ x(x + 24) – 20(x + 24) = 0
⇒ (x + 24)(x – 20) = 0
⇒ (x + 24) = 0 or (x – 20) = 0
∴ x = –24 or x = 20 Since x cannot be negative, x = 20Hence his original duration of the tour is Rs 20
I Hope It Will Help!
^_^
Amount with the person = Rs 360
Let the original number of duration of the tour be x days
Daily expenses per day = Rs 360/xGiven that his tour is extended for 4 days
Hence per days = Rs 360/(x + 4)
∴
⇒ 360x + 1440 – 360x = 3(x2 + 4x)
⇒ 1440 = 3x2 + 12x
⇒ 3x2 + 12x – 1440 = 0
⇒ x2 + 4x – 480 = 0
⇒ x2 + 24x – 20x – 480 = 0
⇒ x(x + 24) – 20(x + 24) = 0
⇒ (x + 24)(x – 20) = 0
⇒ (x + 24) = 0 or (x – 20) = 0
∴ x = –24 or x = 20 Since x cannot be negative, x = 20Hence his original duration of the tour is Rs 20
I Hope It Will Help!
^_^
shwetankmishra4:
thanks for helping me .
but there is a problem it is 30 not 3.
"he has to cut down his daily expenses by Rs. 30" --- read the line carefully.
oh!
thank you
that question was came in my exam today..
Ooooo...
(^•^)
hmm
AND IT CANNOT BE SOLVED IN PERFECT NUMBER OF DAYS.
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