Question

A person operates microwave oven of 2KW power rating in a domestic circuit of 220V and current 5A. What result is expected

Answer 1

In this problem we have

Power of the oven (P) = 2 kW = 2000 W

Potential Difference (V) = 220 V

We have P = VI

⇒I=P/V

   = 2000/220

   = 9.09A

Explanation-----

Here the current drawn by the electric oven is 9.09 A, which exceeds the safe limit of the circuit that is 5A. Therefore electric fuse will melt and break the circuit.

Answer 2

ANSWER :

P max = 2000 W

V = 220 V

I max = 5 A

P= VI

I= P/V

I=2000/220

I=100/11

I=9.09 A

Since the current is greater than the current rating( I max) the oven is going to short circuit.

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