A person playing golf is getting ready to hit the ball. After they hit the ball it reaches a max speed of 70m/s. Assuming the mass of the golf ball is 0.05kg, how much work does the golfer do on the ball?
Answers
Please find the attachment ✌️
Answer:
Take eg
Explanation:
mass of the ball (m) =100g or 0.1kg
initial velocity (u) =25
s
m
time (t) = 0.025sec.
final velocity (v) = 0
Initial momentum = mu
= 0.1×25
= 2.5
s
kgm
Final momentum = mv (which is equal to 0, since v is zero)
Change in momentum = mv-mu
= 0 - 2.5 = -2.5
s
kgm
Average force =
time
Changeinmomentum
= -
0.025
(2.5)
= -100
s
kgm
= -100 N
The negative sign actually shows that the force was applied
opposite to the direction of the motion of the ball.
So, the average force applied by the player will be 100