A person purchases the following items from a mall for which the sales tax is mentioned against:
(a) Stationery materials for ₹ 250 and sales tax of 4% there on;
(b) Electronic goods worth ₹ 2,580 and sales tax of 10% there on;
(c) Groceries worth ₹ 1,200 on which sales tax of 3% is levied;
(d) Medicines worth ₹ 200 with sales tax of 6%.
Find the bill amount for each item.
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Solution :
i ) Cost price of stationary
materials ( c .p ) = Rs250
Sales tax( t ) = 4%
Bill Amount ( A ) = c.p[(100+t)/100]
= 250[(100+4)/100]
= 250 × ( 104/100 )
= Rs 260
__________________________
ii ) Cost price of the item (c.p)=Rs2580
Sales tax (t) = 10%
tax = 10% of 2580
= ( 10/100 ) × 2580
= Rs 268
Bill amount = c.p + sales tax
= Rs 2580 + Rs 268
= Rs 2848
___________________________
iii ) Cost price of the item (c.p) = Rs 1200
sales tax ( t ) = 3%
t = 3% of 1200
= ( 3/100 ) × 1200
= Rs 36
Bill amount = c.p + t
= 1200 + 36
= Rs 1236
___________________________
iv ) Cost price of the item (c.p)= Rs200
sales tax ( t ) = 6%
Bill amount = c.p[ (100+t)/100 ]
= 200[ (100 + 6 )/100 ]
= 200 × ( 106/100 )
= 2 × 106
= Rs 212
•••••••
i ) Cost price of stationary
materials ( c .p ) = Rs250
Sales tax( t ) = 4%
Bill Amount ( A ) = c.p[(100+t)/100]
= 250[(100+4)/100]
= 250 × ( 104/100 )
= Rs 260
__________________________
ii ) Cost price of the item (c.p)=Rs2580
Sales tax (t) = 10%
tax = 10% of 2580
= ( 10/100 ) × 2580
= Rs 268
Bill amount = c.p + sales tax
= Rs 2580 + Rs 268
= Rs 2848
___________________________
iii ) Cost price of the item (c.p) = Rs 1200
sales tax ( t ) = 3%
t = 3% of 1200
= ( 3/100 ) × 1200
= Rs 36
Bill amount = c.p + t
= 1200 + 36
= Rs 1236
___________________________
iv ) Cost price of the item (c.p)= Rs200
sales tax ( t ) = 6%
Bill amount = c.p[ (100+t)/100 ]
= 200[ (100 + 6 )/100 ]
= 200 × ( 106/100 )
= 2 × 106
= Rs 212
•••••••
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