Question

A person's salary is always 6/5 times his previous month salary.his average salary for 4 months was rs.1342 .what was his frist month*s salary

Answer 1

The person’s first moth’s salary was Rs. 1000.

Step-by-step explanation:

Let the person's first month salary be Rs. "P".

 It is given that his salary is always $\frac{6}{5}$ times his previous month's salary

So, we have

The salary for the 2nd month = $\frac{6}{5} * P$

The salary for the 3rd month = $\frac{6}{5} * (\frac{6}{5}P) = \frac{36}{25} P$

The salary for the 4th month = $\frac{6}{5} * (\frac{36}{25}P) = \frac{216}{125} P$

The person's average salary for 4 months is given as Rs. 1342

Therefore, we can also write as,

Average Salary for 4 months = [sum of the salary for each month] / [No. of months]

substituting the values

⇒ $1342 = \frac{P + \frac{6P}{5} + \frac{36P}{25} + \frac{216P}{125} }{4}$

⇒ $5368 = P [1 + \frac{6}{5} + \frac{36}{25} + \frac{216}{125} ]$

⇒ $5368 = P [\frac{125+150+180+216}{125} ]$

⇒  P = $\frac{5368 * 125}{671}$

⇒ P = 8 * 125

⇒ P = Rs. 1000 ← the person's first month's salary

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