Question

A person sells two articles together for Rs. 46, making a profit of 10% on one and 20% on the other. If he had sold each article at 15% profit, the result would have been the same. At what price does he sell each article ?

Answer 1

Let the CP of 1st article be x.

So,SP of 1st article =x + x/10 = 11x/10

And,SP of 2nd article =46−x + 46−x/5 = 6(46-x)/5

Therefore,SP of both articles = 11x/10+6(46-x)/5 = 552 - x/10

If he sold the article of 15% profit,total SP = x + 15x/100 + 46-x + 15/100(46-x) = 529/10

Now,According to the question,

552 - x/10 = 529/10

=> x = 552−529=23.

Therefore,SP of each article = 11/10 × 236/5 × (46-23)

Amount=Rs25.3 and Rs.27.6.

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Answer 2

Answer:

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Step-by-step explanation:

Let the CP of 1st article be x.

Therefore, CP of 2nd article = 46-x.

Now, profit of 1st article = x/10.

and, profit of 2nd article = 20(46-x)/10 = 46-x/5.

So, SP of 1st article = x+x/10 = 11x/10.

And, SP of 2nd article = 46-x + 46-x/5 = 6(46-x)/5.

Therefore, SP of both articles= 11x/10 + 6(46-x)/5 = 552-x/10.

If he sold the article of 15% profit total SP = x+15x/100+46-x+15/100 (46-x) = 529/10.

Now, According to the question

552-x/10=529/10

x= 552-529 = 23.

Therefore, SP of each article = 11/10×23 & 6/5 (46-23) .

Rs 25.3 & Rs 27.6