A person sitting at the top of a tall building is dropping balls at regular intervals of 1 second. Find the position of the 3rd, 4th and 5th ball when the sixth ball is being dropped.
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Answers
When the sixth ball was dropped, 5 seconds have elapsed
from the time the first ball was dropped, 4 seconds after the
second ball was dropped, 3 seconds after the the third ball was
dropped, 2 seconds after the fourth ball was dropped and 1 second
after the fifth ball was dropped.
Thus being said, when the sixth ball was dropped & since the 3rd ball
has been falling for 3 seconds, then
D3 = (1/2)(9.8)(3^2) = 44.1 meters
Since the fourth ball has been falling for 2 seconds,
D4 = (1/2)(9.8)(2^2) = 19.6 meters
and since the fifth ball has been falling for 1 second,
D5 = (1/2)(9.8)(1)^2 = 4.9 m
Explanation:
When the sixth ball was dropped, 5 seconds have elapsed
from the time the first ball was dropped, 4 seconds after the
second ball was dropped, 3 seconds after the the third ball was
dropped, 2 seconds after the fourth ball was dropped and 1 second
after the fifth ball was dropped.
Thus being said, when the sixth ball was dropped & since the 3rd ball
has been falling for 3 seconds, then
D3 = (1/2)(9.8)(3^2) = 44.1 meters
Since the fourth ball has been falling for 2 seconds,
D4 = (1/2)(9.8)(2^2) = 19.6 meters
and since the fifth ball has been falling for 1 second,
D5 = (1/2)(9.8)(1)^2 = 4.9 m