Question

a person sitting on top of a tall building is dropping balls at regular intervals of 1sec. When the 6th ball is being dropped the positions of 3rd,4th,5th balls from the top of the building are respectively.
(1)4.9m,19.6m,44.1m
(2)4.9m,14.7m,24.5m
(3)44.1m,19.6m,4.9m
(4)24.5m,14.7m,4.9m.​

Answer 1

Answer:

Explanation:

Height of fall of balls are given by the equation, h=ut+½gt² =½gt² (Since u=0) For the 3rd ball t=3 s, So h=½*9.8*9 =44.1 m below the top of the building. For the 4th ball t=2 s, So h=½*9.8*4 =19.6 m below the top of the building. For the 5th ball t=1 s, So h=½*9.8*1 =4.9 m below the top