Math, asked by bayojuharish, 18 hours ago

A PERSON SPENT RUPEES. 564IN BUYING PENS AND PENCILS IF COST OF EACH PEN IS RUPEES.7 AND EACH PENCIL IS RUPEES IF THE TOTAL NUMBER OF THINGS BOUGHT WAS 108,HOW MANY OF EACH TYPE DID HE BUY ?

Answers

Answered by doomsdayorigins9128
0

Answer:

Let the number of pens be x

Therefore the number of pencils = Total – number of pens = 108 – x

Now cost of x pens = Cost per pen × number of pens = 7x

Similarly cost of pencils = cost per pencil × number of pencils = 3(108 – x)

Given total amount spent = Rs.564

Total amount = cost of total pens + cost of total pencils

⟹7x + 3(108 – x) = 564

⟹7x – 3x + 324 = 564

⟹4x = 240

⟹x = 2404=60

Therefore 108 –x = 108 – 60 = 48.

Hence, the number of pens are 60 and the number of pencils are 48.

Answered by aradhyasrivastava78
0

Answer:

Pen - 60

Pencil - 48

Step-by-step explanation:

Let the number of pens be x

Therefore the number of pencils = Total – number of pens = 108 – x

Now cost of x pens = Cost per pen × number of pens = 7x

Similarly cost of pencils = cost per pencil × number of pencils = 3(108 – x)

Given total amount spent = Rs.564

Total amount = cost of total pens + cost of total pencils

⟹7x + 3(108 – x) = 564

⟹7x – 3x + 324 = 564

⟹4x = 240

⟹x = 2404=60

Therefore 108 –x = 108 – 60 = 48.

Hence, the number of pens are 60 and the number of pencils are 48.

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