A person standing away from a cliff hears an echo after x seconds. On approaching the cliff by a metres he hears an echo after y seconds. Prove that the velocity of sound in air is 2a/x-y.
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first echo = x
second echo y
cliff =a
2(x-y)=a
=> 2a/x-y
hence proved
second echo y
cliff =a
2(x-y)=a
=> 2a/x-y
hence proved
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