a person standing between the 2 vertical cliffs produces a sound. two successive echoes are heard at 4s and 6s . calculate the distance between the cliffs.(speed of sound in air = 320m/s).
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Answer:
1600
Explanation:
We have the formula : t1+t2= 2l/v
Where l is the distance b/w the cliffs. Apply the formula in the given question.
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