A person standing on the bank of a river observes that the angle of elevation of the top of a tree standing on the opposite bank is 60°. When he moves 40 metres away from the bank, he finds the angle to be 30°. Find the height of
the tree and the width of the river.
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Let DC be tree of height h m BC be the river width X metre and A be the position of man after moving 40 m.
Given:
AB= 40 m, angle DAC = 30° angle DBC = 60°
Solution is in the attachment.
Hence, the height of the tree is 20√3 metre & width of the tree is 20 m
=====≠============================================================================
Hope this will help you.....
Given:
AB= 40 m, angle DAC = 30° angle DBC = 60°
Solution is in the attachment.
Hence, the height of the tree is 20√3 metre & width of the tree is 20 m
=====≠============================================================================
Hope this will help you.....
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