Question

A person standing on the floor of an elevator drops a coin. The coin reaches the floor of the elevator in time t1 if the elevator is stationary and in time t2 if it is moving uniformly. Then
(a) t1 = t2
(b) t1 < t2
(c) t1 > t2
(d) t1 < t2 or t1 > t2 depending on whether the lift is going up or down.

Answer 1

Answer:

t1=t2

Explanation:

as the lift is moving uniformly the acceleration is zero

expression for the time can be given by the formula ,

$s = ut + \frac{1}{2} at ^{2}$

where

u=0

s=h

a=g

Answer 2

the answer is

the option $(a) t1 = t2$

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