A person standing on the ground observes the angle of elevation of the top of a tower to be 30 degree. On walking a distance a in a certain direction, he finds the elevation of the top to be same as before. He then walks a distance 5/3 a at right angles to his former direction and finds that the elevation of the top has doubled. The height of the tower is
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We will assume h be the height of the building.
ΔABC tan 60° = AB/BC
√3 = h/x
x = h/√3
And in the Right Angle ABD,
tan 30° = AB/BD
= 1/√3 = h/ x + 50
= h/√3 + 50 = √3h
h = 25√3m
If there is any confusion please leave a comment below.
ΔABC tan 60° = AB/BC
√3 = h/x
x = h/√3
And in the Right Angle ABD,
tan 30° = AB/BD
= 1/√3 = h/ x + 50
= h/√3 + 50 = √3h
h = 25√3m
If there is any confusion please leave a comment below.
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