Physics, asked by riddhish0106, 6 months ago

a person standing on vertical cliff at height of 180 m above a lake,wantsto jump into the lake but notiecs a rock at the surface level with its furthest edge a distance s from the shore the person realises that with the running start it will be possile to just clear the rock.so the person steps back from the edge a distance d=125/3 and starting freom rest runs at an accelearation that varries in time according to a(x)=2t and then leaves the cliff horizontally.the person just clears the rock.find k if s=k50(take g=10cm/sec(^2) )

Answers

Answered by vasanthkumarvasanth5
0

Answer:

A metal cannonball of mass m rests next to a tree at the very edge of a cliff 36.0 m above the surface of the ocean. In an effort to knock the cannonball off the cliff, some children tie one end of a rope around a stone of mass 80.0 kg and the other end to a tree limb just above the cannonball. They tighten the rope so that the stone just clears the ground and hangs next to the cannonball. The children release the stone, which then swings down and makes a head-on, elastic collision with the cannonball, projecting it horizontally off the cliff. The cannonball lands in the ocean a horizontal distance R away from its initial position.

What if? Show that R does not depend on the value of the gravitational acceleration. Is this result remarkable? State how one might make sense of it.

Answered by 3904layanasakthi
0

Explanation:

Correct option is

B

0.5

Velocity of the body at point A u

A

=0

Let the velocity of body at points B and C be u

B

and u

C

resp

⟹ t

AB

=0.5 s

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