Math, asked by sonia9220, 1 year ago

A person started his journey in the morning. At 11 a.m. he covered 3/8 of the journey and on the same day at 4:30 p.m. he covered 5/6 of the journey. He started his journey at?

Answers

Answered by SpartanSubha
4
He starts journey at 6:30 AM.
Hope you get the answer.

SpartanSubha: the time interval or time difference is 4:30PM-11AM =5hr30min =330min
SpartanSubha: So he covered 11x/24 distance in 330min
SpartanSubha: 11x/24 = 330min
SpartanSubha: x = 330* 24/11 min = 720min
SpartanSubha: it means total time travel from 1st point to last is 720min or 12hrs.
SpartanSubha: so, x/6 distance will take = 720min/6 =120min
SpartanSubha: 120min = 2hrs
SpartanSubha: it means he will reach at his destination after 2 hrs of 4:30PM =6:30PM
SpartanSubha: As the total time taken is 12hrs, and the time at the destination is 6:30PM. Then he starts his journey from 6:30AM
SpartanSubha: Hope you get the answer
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