Question

a person started his Motion from rest with constant acceleration of 0.4 m/s after sometime the velocity becomes 18 m/s find out the displacement if he travels in a straight line​

Answer 1

$\sf{\large{\underline{\underline{EXPLANATION}}}}$

$\sf{Given}\begin{cases}\sf{u=0ms^{-1}}\\ \sf{v=18ms^{-1}}\\ \sf{a=0.4ms^{-2}}\end{cases}$

$\textbf{\underline{To find:}}</p><p>$

$\mathtt{\boxed{\blue{s=??}}}$

$\textbf{\underline{Using equation of motion,,}}</p><p>$

$\mathtt{\boxed{\blue{v^{2}-u^{2}=2as}}}$

$\textbf{\underline{Putting values,,}}</p><p>$

$\sf{18^{2}-0^{2}=2\times{0.4}\times{s}}$

$\sf{\implies{324=0.8\times{s}}}$

$\sf{\implies{\cancel\dfrac{3240}{8}=s}}$

$\sf{\implies{s=405m}}$

Therefore,,

$\mathtt{\boxed{\red{s=405m}}}$

$\rule{200}2$

Hope it helps ❣️❣️❣️

Answer 2

Hey This is the answer 405 m

Hope it helps.

please mark it as brainliest