Question

a person starts his job with a monthly salary of 5000 and earn a fixed increment after every year.If he gets 6000 after 5 years.Find his annual increment​

Answer 1

Answer:

SOLUTION

the starting salary of the man be Rs. x and the fixed annual increment be Rs. y. Then,

Salary after 4 years of service =Rs. (x+4y)

Salary after 10 years of service =Rs. (x+10y)

x+4y=1500

x+10y=1800

Substracting equation (i) from equation (ii), we get

6y=300⇒y=50

Putting y=50 in equation (i), we get x=1300.

Hence the starting salary was Rs. 1300 and annual increment is Rs. 50.