Question

a person strikes a nail with the hammer of mass 500 gram moving with a velocity of 10 metre per second the hammer comes to rest in 0.01 second striking the nail calculate the force exerted by hammer on the need and also distance moved by the nail into the plank​

Answer 1

• Force=500N
• S=.4m

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Answer 2

Explanation:

It is given that,

Mass of the hammer, m = 500 gm = 0.5 kg

Initial velocity of the hammer, v = 10 m/s

Finally, it comes to rest, u = 0

Time taken, t = 0.01 s

We need to find the force exerted by hammer on the nail and also distance moved by the nail into the plank​. Let F is the force.

$F=m\times a$

a is the acceleration, $a=\dfrac{v-u}{t}=\dfrac{10}{0.01}=1000\ m/s^2$

$F=m\times (\dfrac{v-u}{t})$

$F=0.5\ kg\times (\dfrac{10\ kg}{0.01\ s})$

F = 500 N

Let s is the distance moved by the nail into the plank​. It can be calculated using third equation of motion as :

$v^2-u^2=2as$

$s=\dfrac{v^2-u^2}{2a}$

$s=\dfrac{10^2}{2\times 1000}$

s = 0.05 m

Hence, this is the required solution.