A person strolls inside a train with a velocity of 1.0 m s–1 in the direction of motion of the train. If the train is moving with a velocity of 3.0 m s–1, calculate his (a) velocity as seen by passengers in the compartment, and (b) velocity with respect to a person sitting on the platform.
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Answer:
a)1 ms⁻¹
b)2 ms⁻¹
Explanation:
a) since passenger is on the train he can directly see the person who strolls
hence,
vₐ , passenger = 0 ms⁻¹
vᵇ , the person who strolls = 1 ms⁻¹
vᵇₐ = vb - va
= 1-0
= 1ms⁻¹
b) the observer is sitting on the platform and the person inside the train who strolls as well the train move in the positive direction therefore,
vb , the velocity of the train = 3ms⁻¹
va , the velocity of the person who strolls= 1ms¹
vᵇₐ = vb - va
= (+3)-(+1)
= 2ms⁻¹
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