Question

A person suffering from far sightedness wears spectacles having a convex lens of focal length of 50cm. What is the distance of the near point of his eye?

Answer 1

Answer:

the distance of near point of his eye is equal to 1 upon 50 e is equal to power of lens that is 0.02 D

Answer 2

Dear Student,

◆ Answer -

Distance of the near point of his eye = 50 cm.

● Explanation -

For the normal person, least distance of distinct vision is 25 cm. Given that person uses convex lens of focal length 50 cm. Now let v be distance of near vision.

Using lens formula,

1/f = 1/v - 1/u

1/50 = 1/v - 1/-25

1/50 - 1/25 = 1/v

1/v = -1/50

v = -50 cm

Hence, the distance of the near point of his eye is 50 cm.

Thanks dear. Hope this helps you..