Question

A person suffering from hypermetropia has near point as `100 cm`.The focal length of the lens to correct his vision is​

Answer 1

Answer:

The focal length of a lens suggested to a person with Hypermetropia is 100cm. Find the distance of near point and power of the lens.

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Answer

Given: The focal length of a lens suggested to a person with Hypermetropia is 100cm.

To find the distance of near point and power of the lens.

Solution:

Let the distance of near point be ’d’ and focal length be 'f=100cm' then

f=

d−25

25d

cm

⟹100(d−25)=25d

⟹100d−25d=2500

⟹d=

75

2500

⟹d=

3

100

=33.33cm

Hence the distance of near point will be 33.33cm

We know,

Power, P=

f

1

D, f is in metres

⟹P=

100×10

−2

1

⟹P=1D

is the power of the lens.