if (a^2+4a+4)x^2+(a^2-4)x+(a+2)=0 has more than two roots then find the value of "-a"
Answers
Answered by
0
Answer:
If a = −1, then quadratic equation has more than two roots.
Step-by-step explanation:
(a2 + 4a + 3)x2 + (a2 - a - 2)x2 + (a2 - a - 2)x + (a + 1)a = 0
⇒ (a + 1)(a + 3)x2 + a + 1)(a - 2)x + (a + 1)a = 0
⇒ (a + 1)[(a + 3)x2 + (a - 2)x + a] = 0
Similar questions