Question

A person swims 100m in the first 40s. 80m in the next 40s and 45m in the last 20s. what is the average speed.​

Answer 1

Question :-

A person swims 100m in the first 40s. 80m in the next 40s and 45m in the last 20s. what is the average speed.

Answer :-

• Average speed = 2.25m/s²

Step by step explanation :-

Given :

• A person swims 100m in the first 40s. 80m in the next 40s and 45m in the last 20s.

Need to find :-

• Average speed

Required formula :-

$\rm:\longmapsto{Average \: Speed = \frac{Total \: distance }{Total \: time }}$

Let,

$\rm \bull \: {100m = d_{1}} \\ \\ \rm \bull \: {80m = d_{2}} \: \: \\ \\\rm \bull \: {45m = d_{3} \: } \:$

And,

$\rm \bull \: {40s = t_{1}} \: \\ \\ \rm \bull \: {40s = t_{2}} \: \: \\ \\\rm \bull \: {20s = t_{3} \: } \: </p><p>$

• Average speed :

$\rm:\longmapsto{Average \: Speed = \frac{d_1 + d_2 + d_3 }{t_1 + t_2 + t_3}}$

On substituting all values we get,

$\rm:\longmapsto{Average \: Speed = \frac{100 + 80 + 45}{40 + 40 + 20} } \\ \\ \rm:\longmapsto{Average \: Speed = \frac{225}{100} } \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \: \\ \\ \bf:\longmapsto \red{Average \: Speed = 2.25m</p><p>/s {}^{2} } \: \: \:$

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