Question

A person threw a standard dice 3 times distinct odd prime numbers in two throws and an even number which is not a factor of 18 in the third throw. The sum of all the numbers on the opposite faces of numbers obtained in the three throws is9121015

Answer 1

3,5 are odd ,prime numbers in the dice.

Answer 2

Answer:  The answer is 9.

Step-by-step explanation:  We know that a dice has 6 numbers 1, 2, 3, 4, 5 and 6. The person had thrown a dice three times.

In the first two throws, distinct odd primes occur, which are 3 and 5. In the third throw 4 comes up, because it is the only even number out of six numbers which is not a multiple of 18.

In a dice, the pairs of opposite numbers are (1,6), (2,5) and (3,4).

Therefore, the sum of all numbers on the opposite faces of 3, 5 and 4

=4+2+3=9.

Thus, the required sum is 9.