Question

a person throws a ball of mass 100 gram with a speed of 20meter per second . It came to rest after 5 second . Find the average force applied by the person.



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Answer 1

Given:

• Mass of ball ,m = 100g = 0.1 kg
• Initial velocity ,u = 20m/s
• Final velocity ,v = 0m/s
• Time taken ,t = 5 s

To Find:

• the Average Force applied by the Person =?

Formula used:

$\bigstar\:{\underline{\boxed{\frak{\purple{ F=ma}}}}}$

Solution:

we know that ,

$:\implies\bf\; F= m a$

${\dag}\:{\underline{\frak{putting\:given\:values\:in\:formula,}}}$

$:\implies \sf\; Force = m \frac{v-u}{t}$

$:\implies \sf\; Force = 0.1 \times\frac{0-20}{5}$

$:\implies\sf\; Force= 0.1\times\frac{-20}{5}$

$:\implies\sf\; Force = 0.1\times (-4)$

$:\implies\bf\red\; Force = -0.4N$

$:\implies{\frak{ \pink{Force = -0.4 N}}}\:\bigstar$

Hence, the Average Force applied by the person will be 0.4 Newton.

Answer 2

Answer:

Hence, the Average Force applied by the person will be 0.4 Newton.

I hope you have understood the ans