A person travelled at a speed of 50 kmph and missed the bus by 40 minutes. Had he travelled at 60 kmph he
would have still missed the bus by 20 minutes. At what minimum speed should he travel to catch the bus?
plz.. answer it quickly
Answers
Answer:75 km/hr.
Step-by-step explanation:
Let the distance to travel be x km.
A.T.Q.
x/50-x/60=20/60
6x-5x/300=1/3
x=100 km.
Time taken at 50km/hr. As the Speed=100/50=2 hours
Distance=100 km.
Time=2:00-0:40=1:20 minutes
Speed=D/T
=100*3/4
=75 km/hr.
Answer:
Step-by-step explanation:
let the distance of the persons house and the bus stop be :D km
given: person travelled at a speed of 50 kmph and missed the bus by 40 minutes.
WE KNOW THAT : Time =distance / speed
⇒Time taken to reach bus stop with 50 kmph = D/50 hour
given :Person travelled at a speed of 60 kmph he would have still missed the bus by 20 min.
⇒Time taken by person to reach Bus stop with speed 60kmph :D/60 hour
Therefore,
(D/50--D/60) hour = (40-20) minutes
(D/50-D/60)hour = (20) minutes
(D/50-D/60)hour = (1/3) hour
(60D-50D/3000) = (1/3)
(60D-50D/1000) = 1
60D-50D=1000
10D=1000
D= 100KM
⇒Time taken to reach bus stop with 50 kmph = 100/50 hour
⇒Time taken to reach bus stop with 50 kmph = 2hours
⇒Time taken to reach bus stop with 50 kmph = 120minutes
Given: Person traveled at a speed of 50 kmph and missed the Bus by 40min
⇒It means : If the person would have reached the Bus stop in (120-40) minutes , he would be at the Bus stop at right time to catch the bus.
⇒It means : If the person would have reached the Bus stop in 80 minutes , he would be at the Bus stop at right time to catch the bus.
we know that, 80 minutes is : (1+1/3) hour = 4/3hour
⇒minimum speed to catch the bus = 100/(400/3) kmph
⇒minimum speed to catch the bus=(100×3/4) kmph
⇒minimum speed to catch the bus=(25×3)kmph
⇒minimum speed to catch the bus=75 kmph
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