Question

A person travelling at 43.2 km/h applies the brake giving a deceleration of 6.0 m/s2 to his scooter. How far will it travel before stopping ?

plz provide steps

Answer 1

you can see your answer

Answer 2

ʜᴇʟʟᴏ ᴍᴀᴛᴇ!

Let's see what value we have,

u ( initial velocity ) = 43.2 km/h

a ( acceleration ) = - 6 m/s²

v ( final velocity ) = 0

Converting 43.2 km/h into m/s

= 43.2 × 5/18 m/s

= 2.4 × 5 m/s

= 12 m/s

v² - u² = 2as [ Third Equation of Motion ]

0² - (12)² = 2(-6)(s)

- 144 / - 12 = s

12 m = s ( distance )

So, person travel 12 m after applying breaks of 6 m/s²

Hope it helps