A Person travelling at 43.2 kmph applies breaks giving a decelaration of 4 meter per second square to his car find the distance travelled by the car before it comes to rest.
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The distance travelled by the car before it comes to rest should be 18 metres.
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U = 43.2 km / he = 43.2×5÷18=12m/sec
V= 0 m/sec
a= - 4 m /sec square
According to formula
V square = u square +2 as
0= 12×12-2×4×s
8s=144
S=16 m
sangharsh1234:
Plz mark as brilliant
Shouldn't it be 18m, Sangharsh1234?
sry I have mistake
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